8051 code to find a number is even or odd

So the basic logic we use is to check weather a number divides with 2 or not . Here we can use another logic by rotating the value in the accumulator to the right through carry and then make the decision based on  the value of the carry.I will post both the methods..

Method 1: Using DIV instruction
           
            ORG 000h
            MOV A,#number   ;The number to be checked for even or odd
            MOV B,#02h   ;divisor
            DIV AB  ;Divides the unsigned value of the Accumulator by the unsigned value of the “B” register. The resulting quotient is placed in the Accumulator and the remainder is placed in the “B” register.If remainder is 1 then the number is odd.
            
             MOV R0,B
            CJNE R0,#0h,odd
            MOV A,#00h ; moving 0 to show its even
            SJMP even

odd: MOV A,#01h ;moving 1 to accumulator to show the number is odd…you can do any other operation.

even: NOP
END
 
Now why did i add “SJMP even “ is the code executes sequentially ,even there is a label .The compiler does not skip labels. 


METHOD 2: Using RR instruction

            ORG 000h
            MOV A,#number   ;The number to be checked for even or odd
            RRC A ;rotates the accumulator right through carry
            JC  odd
            MOV A,#00h ; moving 0 to show its even
            SJMP even
odd: MOV A,#01h ;moving 1 to accumulator to show the number is odd…you can do any other operation.

even:  NOP
END
 
If the number is odd the it will have the lsb as binary 1,and if even lsb will be binary 0….