ARM assembly code to find number of odd numbers in an array

Let’s see how to write a ARM assembly code to find number of odd numbers in an array.
ALGORITHM

1. Start
2. Load the base address of the array.
3. Initialize a counter register to the number of elements in the array.
4. Initialize a register(Rd) to zero to store number of odd numbers.
5. Load the value from array to a temporary register.
6. AND the value in temporary register with 0x01.
   • If zero flag is not set, increment to register Rd.
   • Else decrement the counter register and jump to step 5.
7. Repeat steps 5-6 till counter value becomes zero
8. Stop

Here is an example code to find the number of odd numbers in an array.
Note: initialize the array at the end of the program without fail, before execution.
CODE

      AREA program,CODE,READONLY
      ENTRY
      MOV R0,#01          ; Storing 0x01 for AND operation
      LDR R1,=array       ; Storing base address of array
      MOV R2,#0X09        ; Initializing counter
lbl   AND R0,[R1],#4      ; 'AND'ing to check whether number is odd or even
      ADDNE R3,R3,#O1     ; R3 register will have count of number of odd numbers.
      SUBS R2,R2,#01
      BPL lbl
array DCD  0x11223343, 0x12345672, 0x002917BD3, 0x00000A01, 0x62398746, 0xAB56E3CE, 0x0A761AC7, 0x623ABC46, 0xAB86E3BD, 0x0A762DE8,
      END