- ARM

ARM Assembly code to find number of positive numbers in an array

Let’s see how to write a ARM assembly code to find number of positive numbers in an array.
ALGORITHM

  1. Start
  2. Load the base address of array.
  3. Initialize a counter register to number of elements in array.
  4. Initialize a register(Rd) to zero to store number of positive numbers.
  5. Load the value from array to a temporary register.
  6. Compare the value with zero
    • If zero flag is not set, increment to register Rd.
    • Else decrement the counter register and jump to step 5.
  7. Repeat steps 5-6 till counter value becomes zero
  8. Stop

Here is a example code to find number of positive numbers in an array.
Note: initialize the array at the end of program without fail, before execution.
CODE

      AREA program,CODE,READONLY
      ENTRY
      LDR R1,=array       ; Storing base address of array
      MOV R2,#0X09        ; Initializing counter
lbl   AND R0,[R1],#4
      CMP R0,#00          ; Comparing with zero
      ADDPL R3,R3,#01     ; R3 register will have count of number of positive numbers.
      SUBS R2,R2,#01
      BPL lbl
array DCD  0x11223343, -0x12345672, 0x002917BD3, -0x00000A01, -0x62398746, 0xAB56E3CE, -0x0A761AC7, 0x623ABC46, -0xAB86E3BD, 0x0A762DE8,
      END

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